A software engineer creates a LAN game where an 8 digit code made up of 1,2,3,4,5,6,7,8 has to be decided on, universal code . There is a condition that each number has to be used a and no number can be repeated . What is the probability that first 4 digits of the code are even numbers ?
Answers
Answered by
91
Answer:
1/70
Step-by-step explanation:
total digits = 8
even digit = 4 ( 2 , 4 , 6 , 8)
odd digit = 4 ( 1 , 3 , 5 , 7)
no repetition
so probability of 1st digit being even = 4/8 = 1/2
2nd digit being even = 3/7
3rd digit being even = 2/6 = 1/3
4th digit being even = 1/5
probability that first 4 digits of the code are even numbers
= (1/2)(3/7)(1/3)(1/5)
= 1/70
Another way :
total combination = 8!
1st 4 even digit combination = 4!
then Last 4 Digit odd combination = 4!
Probability = 4! * 4 ! /8
= 4 * 3 * 2 / (8 * 7 * 6 * 5)
= 1/70
Answered by
11
Answer:
the answer for the question is 1/70
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