Question

a soil deposit has a void ratio of 1 . if the void ratio is reduced to 0.6 by compaction, find the % volume loss.
ans) 20%

anyone with solution ?​

Answer 1

Answer:

Explanation:

12

Answer 2

Given that void ratio =1, ef = 0.6 then the percentage of volume loss :

Explanation:

• ΔV = (Δe/(1+ei) ) * 100
• ΔV⇒ change in volume
• ei ⇒ initial void ratio
• ef⇒ final void ratio
• ef =0.6
• ei = 1
• V_L = ((0.6 - 1)/1+1) *100
• ∵ Volume loss percentage = -20%