Question

A soil sample having mass of 200 g was taken from garden.This soil was dried completely in the oven and again weight. The weight of the soil now was found to be 170 g. Calculate the percentage of water or moisture content present in the sample soil. [HOTS]

Answer 1

Answer:

15%

Explanation:

Initial weight of soil = 200 g

Final weight of soil = 170 g

Weight of moisture = 200 g - 170 g = 30 g

Hence, percentage of moisture = (30/200 * 100) % = 15%

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Answer 2

Given - Wet mass and dry mass

Find - Moisture content

Solution - Moisture content in percentage can be found by the formula - amount of water/original mass*100

Amount of water = original mass - dried mass

Amount of water = 200 - 170

Performing subtraction

Amount of water = 30 gram

Keep the values in formula

Moisture content = 30/200*100

Performing multiplication and division

Moisture content = 15%

Hence, the moisture content in soil sample is 15%.