Question

"a soil sample with a grain specific gravity of 2.67 was filled in a 1000 ml container in the loosest possible state and the dry weight of the sample was found to be 14.75 n. it was then filled at the densest state obtainable and the weight was found to be 17.70 n. the void ratio of the soil in the natural state was 0.63. determine the density index in the natural state."

Answer 1

Answer:

Given:- G=2.67, e=0.63

V=1000mL

mloose=1475gm

mcompcat=1770gm

sd(min)=14751000=1.475g/cm3

sd(min)=6.Pw/1+emax, emax=0.81

sd(max)=17701000=1.77g/cm3

emin=Gsw(sd)max−1=0.508

IDemax−eemax−emin

0.81−0.630.81−0.508

ID=0.596

ID=59.6%