Question

A soil specimen has a water content of 10% and a wet unit weight of 20kn/m3. If the specific gravity of solids is 2.70, determine the dry unit weight , void ratio, and the degree of saturation. Take, w=10kn/m3

Answer 1

Answer:

w = 0.3

G = 2.7

Sr = 1 (∵ it is saturated soil)

We know,

e =

wG

=

0.3 × 2.7

= 0.81

Sr 1

Saturated unit weight,

γsat =

(g + e)γw

1 + e

=

(2.7 + .81) × 10

1 + .81

= 19.39 kN/m3.

Explanation:

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Answer 2

Answer :

= 1 9 . 3 9 k N / m 3 .

Explanation :

Given : A soil specimen has a water content of 1 0 % and a wet unit weight of 2 0 k n / m 3 . If the specific gravity of solids is 2 . 7 0 ,

To find : determine the dry unit weight , void ratio , and the degree of saturation. Take , w = 1 0 k n / m 3

Solution :

w = 0 . 3

G = 2 . 7

Sr = 1  (∵ it is saturated soil)

We know ,

e = w G

= 0 . 3 × 2 . 7

= 0 . 8 1 Sr 1

Saturated unit weight ,

γsat = ( g + e ) γw

1 + e

= ( 2 . 7 + .8 1 ) × 1 0

1 + .81

= 1 9 . 3 9 k N / m 3 .

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