Math, asked by amolgire1999, 10 months ago

A sold a car to B at 15% profit. b sold the car to C at 5% profit for Rs.48300. Find the price at which A has purchased the car.

Answers

Answered by sonabrainly
9

Answer:

Step-by-step explanation:

Person A sold his car to person B at a profit of 20%:

Profit = 20% of x = 0.2x

Selling Price = x + 0.2x = 1.2x

Person B sold it to Person C at a profit of 10%:

Profit = 10% of 1.2x = 0.1(1.2x) = 0.12x

Selling Price = 1.2x + 0.12x = 1.32x

Person C sold it to mechanic at a loss of 9.09%:

Loss = 9.09% of 1.32x = 0.0909(1.32x) = 0.119988x

Selling Price = 1.32x - 0.119988x = 1.200012x

Mechanic spent 10% of his purchasing price:

10% x 1.200012x = 0.1200012x

Total cost = 1.200012x + 0.1200012x = 1.3200132x

Mechanic sold it at a profit of 8.33%to person A :

profit = 8.33% x  1.3200132x = 0.0833 x 1.3200132x = 0.10996

Selling Price = 1.3200132x + 0.10996 = 1.43x

Calculate the loss:

Loss = 1.43x - x = 0.43x

Loss Percentage = (0.43x ÷ x ) x 100 = 43%

Answer: The loss is 43%

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