Question

A sold a table to B at 20%profit B sold the same table to c for ₹750 thereby making a profit of 25%find the price at which A had bought the table


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Answer 1

#ANSWERWITHQUALITY  #BAL

Step-by-step explanation:

Let A had bought the table be x.

A sold the table to B at 20% profit.

Therefore,

Cost price of B = x + {(x*20)/100}

                        = x + x/5

                        = (5x + x)/5

                        = 6x/5

Again B sold the same table to C at 25% profit.

Therefore,

Cost price of C =

$\frac{6x}{5}+\frac{6x*25}{5*100}\\=\frac{6x}{5}+\frac{3x}{10}\\=\frac{12x+3x}{10}\\=\frac{15x}{10}$

According to the problem,

C had bought the table for Rs. 750

$\frac{15x}{10}=750\\=>15x=750*10\\=>x=\frac{7500}{15}\\=>x=500$

∴A had bought the table for Rs. 500

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