Question

A sold an article to B at a profit of 2.5%, B sold the same article to c at loss of 10%. if c paid ₹9.90 for it , how much did it cost to. A

Answer 1

Let article =x
With profit of 2.5%=x+2.5x/100
With loss of 10%=(x+2.5x/100)*10/100=102.5x/100
Now new cost=102.5x/100-102.5x/1000
=92250x/100000=9.9
X= 10.73
So cost=10. 73

Answer 2

The article cost for A is about 10.73 Rs.

Step-by-step explanation:

Given:

A sold an article to B at a profit of 2.5%, B sold the same article to c at loss of 10%. if c paid 9.90 for it , how much did it cost to. A

Solution:

Let the price of article be x

Profit of 2.5 % = x + 2.5% of x

Loss of 10% = $(x + \frac{2.5x}{100}) \times \frac{10}{100} = \frac{102.5}{100}$

New cost = 9.9  Rs.

Equating to x,

We get x = 10.73  Rs.

The article cost for A is about 10.73 Rs.

To know more:

Mr. A sold an article to Mr. B at a profit of 2.5%. B sold the same to Mr. C at a loss of 10%. If C paid ₹9.90 for it, how much did it cost A?

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