Question

A sold an article to B at a profit of 20% and B sold the article to C at a profit of 25%. A bought the article at a price of rupee 25000. At what price did C buy the article?

Answer 1

Answer:

Step-by-step explanation:

Let the article costs 'x' to A

a' sold an article to 'b' at a profit of 20%.

CP of B = x+20\% x = x+\frac{20}{100}x = 1.2x

Cost price of B = 1.2x

'b' sold the same article to 'c' at a loss of 25%

CP of C =  1.2x-25\% (1.2x) = 0.9x

Cost price of C = 0.9Xx

'c' sold the same article to 'd' at a profit of 40%.

CP of D = 0.9x+40\% (0.9x) = 1.26x

We are given that 'd' paid rs 252 for the article

So,  1.26 x= 252

x= \frac{252}{1.26}

x = 200

Answer 2

Answer: 37500

Step-by-step explanation:

A sold at Rupees= 25000+20%=30000

B sold at Rupees= 30000+25%=37500

Hence, C buy the article at 37500 rupees