Question

A sold car to B at a profit of 20%. B sold the
same car to C at a loss of 25%. If C paid Rs
9,000 to B, find the cost of A.​

Answer 1

Step-by-step explanation:

Let the price at B purchased car be 'x'

25% of x = 25/100×x = x/4

ATP :

x-x/4 = 9000

4x-x/4 = 9000

3x= 36000

x = 36000/3

x = 12000

Profit of A = 100×12000/100+20 = 100×12000/120 = 10000

CP of car for A was ₹10000

Answer 2

$\sf \large \red{\underline{ Question:-}}$

• A sold car to B at a profit of 20%. B sold the same car to C at a loss of 25%. If C paid Rs 9,000 to B, find the cost of A.

$\\\\\sf \large \red{\underline{Given:-}}$

• $\sf \: profit \: of \: A( g_{1}) = 20\% \\ \\ </li><li></li><li>$
• $\sf \: Profit \: of \: B ( g_{2} )= 25\%$

• $\sf \: \: C \: paid \: Rs \: 9,000 \: to \: B.$

$\\\\\sf \large \red{\underline{To \: Find:-}}$

• $\text{ \underline{find the cost of A : }}$

$\\\\\sf \large \red{\underline{Solution :- }}$

$\boxed{ \sf \red{Cost \: price \: of \: a =\frac{C.P\times 100}{100+g_{1}}\times \frac{100}{100+g_{2}}}}$

$\\ \\ \sf\underline{putting \: all \: values : \huge \dag}$

$\sf \to\frac{9000\times 100}{100+20} \times \frac{100}{100+25} \\ \\ \sf \to \: 450 \times \frac{100}{125} \\ \\ \sf \to \: 450 \times \frac{4}{5} \\ \\ \sf \to \: 90 \times 4 \\ \\ \sf \to \: 360$

$\sf \underline{ \sf \red{ the \: cost \: of \: a \: is \: \large \: 360 \: } \huge \: \dag}$