A sold his motorcycle to B at a loss of 28%, B spent Rs.1680 on its repair and sold the motorcycle to C for Rs 35910, thereby making a profit of 12.5%. Find the CP of motorcycle for A.
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A sold his motorcycle to B at a loss of 28%, B spent Rs.1680 on its repair and sold the motorcycle to C for Rs 35910, thereby making a profit of 12.5%. Find the CP of motorcycle for A. Therefore, cost price of A is Rs 42,000.
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Sol:
Let CP of A = Rs x
SP of A = (72/100) x = 0.72 x [There is a loss of 28%]
CP of B including the cost of repairs = (0.72x + 1680)
SP of B = Rs 35910
Profit Percentage = 12.5%
[(35910) - (0.72x + 1680)] x 100 / (0.72x + 1680) = 12.5
⇒ (3423 - 0.72x) / (0.72x + 1680) = (125 / 100)
⇒ 3423000 - 72x = 9x + 21000
⇒ 3423000 - 21000 = 9x + 72x
⇒ 3402000 = 81x
⇒ x = 42000
Therefore, cost price of A is Rs 42,000.
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