A solenoid 1.5 m long and 4.0 cm in diameter possesses 10 turns/cm. A current of 5 A is flowing through it. Then the magnetic induction (1) inside and (ii) at one end on the axis of solenoid are respectively
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Explanation:
B=μnI where n is no of turns per unit length
∴ B= (4π x 10^-7)(10/0.01)(5)=6.28 x 10^-3T
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