Question

A solenoid 3 cm in length carries a current of 400 mA. If

the solenoid is to produce a magnetic flux density of 5 m

Wb/m2

, how many turns of wire are needed?​

Answer 1

Explanation:

B = Uo N I

5 x 10 ^ - 3 = 4 π x 10^-7 x N x 400 x 10^-3

5 = 16 π x 10^-5 x N

N = 5 /( 16π ) x 10⁵

n/l = 5 / 16π x 10⁵

n = 0.03 x 5/ 16π x 10⁵

= 15/16π x 10⁷

Answer 2

Answer:

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