a solenoid 4 cm in diameter and 20 CM in length has 250 turns and carries a current of 15 ampere calculate the flux through the surface of a disc of 10 cm radius that is positioned perpendicular to and centred on the axis of the solenoid.?
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The magnetic flux through the coil is 0.0185 Volt-sec
Explanation:
R = radius of solenoid = 2 cm
L = 20 cm
Turns = N = 250 turns per unit length = n = 1,250 turns/meter
Current through the solenoid "i" = 15 A
Magnetic field through the solenoid = μ₀ n i = 4π x 10⁻⁷ x 1,250 x 15 units B = 2.356 x 10⁻² H
The magnetic field outside the turns of the solenoid is zero.
The magnetic field exists only in the area of π r².
Flux = Magnetic field x area
= B x πr²
= 0.0185 Volt-sec
Thus the magnetic flux through the coil is 0.0185 Volt-sec\
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