Physics, asked by rahulsalva1039, 1 year ago

A solenoid 50cm long has 4 layers winding of 350 turns each if the current carried is 6 A .extimate the magnitude of magnetic field Near the Center of the solenoid of its axis

Answers

Answered by abhi178
10

Therefore the Magnetic field near the centre of solenoid is 2.11 × 10¯² T .

Given : A solenoid 50cm long has 4 layers winding of 350 turns each if the current carried is 6 A.

To find : The magnitude of magnetic field near the centre of the solenoid of its axis.

solution : number of turns per unit length, n = (4 × 350)/(50/100 m)

= 2800 turns per metre.

current passing through the solenoid, I = 6 A

we know, Magnetic field near the centre of the solenoid of its axis is given by, B = μni

= 4π × 10^-7 × 2800 × 6

= (4π × 28 × 6) × 10^-5 T

= 2,110.08 × 10^-5 T

= 2.11 × 10¯² T

Therefore the Magnetic field near the centre of solenoid is 2.11 × 10¯² T

Answered by sehrali3b
1

Answer:

number of turns per unit length, n = (4 × 350)/(50/100 m)

= 2800 turns per metre.

current passing through the solenoid, I = 6 A

we know, Magnetic field near the centre of the solenoid of its axis is given by, B = μni

= 4π × 10^-7 × 2800 × 6

= (4π × 28 × 6) × 10^-5 T

= 2,110.08 × 10^-5 T

= 2.11 × 10¯² T

Therefore the Magnetic field near the centre of solenoid is 2.11 × 10¯² T

Explanation:

Plz mark as brainliest ...i really need one brainliest

Similar questions