Question

A solenoid has 1000 turns per meter length. If current of 5 A is flowing through it, then the magnetic field inside the solenoid is

Answer 1

magnetic field inside the solenoid is 6.28 × 10¯³ T.

It has given that a solenoid has 1000 tunes per meter length, if current of 5A is flowing through it.

we have to find the magnetic field inside the solenoid.

you know, magnetic field of solenoid inside the solenoid is given by, B = μni

where μ is permeability of vacuum i.e., μ = 4π × 10^-7 N/A² , n is number of turns per unit length and i is current through solenoid.

magnetic field, B = 4π × 10^-7 N/A² × 1000/L × 5A

= 4π × 10¯⁴ × 5 T

= 2π × 10¯³ T

= 6.28 × 10¯³ T

therefore magnetic field inside the solenoid is 6.28 × 10¯³ T.

also read similar questions : Current flowing through a long solenoid is varied. Then, magnetic flux

density of the magnetic field inside it varies:

https://brainly.in/question/1933365

a solenoid of length 0.5 m has a radius of 1 cm and is made up of 500 turns it carries a current of 5 ampere what is the...

https://brainly.in/question/7884322

Answer 2

Given that,

A solenoid has 1000 turns per meter length.

Current = 5 A

We need to calculate the magnetic field inside the solenoid

Using formula of magnetic field

$B=\mu_{0}nI$

Where, $n =\dfrac{N}{l}$ = turns per meter length

I = current

B = magnetic field

Put the value into the formula

$B=4\pi\times10^{-7}\times1000\times5$

$B=0.00628\ T$

$B=6.28\times10^{-3}\ T$

$B=6.28\ mT$

Hence, The magnetic field inside the solenoid is 6.28 mT.

Learn more :

Topic : magnetic field

https://brainly.in/question/13427081