Question

A solenoid has a core of material with relative permeability 500 and its windings carry a current of 1 A. The number of turns of the solenoid is 500 per meter. Calculate the magnetization

Answer 1

Answer:

Here, n=5000turns/m

I=1A,μr=500

Magnetic intensity,H=nI=500m−1×1A=500Am−1

As,μr=1+χ

Where, χ is the magnetic susceptibility of the material

orχ=(μr−1)

Magnesium, M=χH

=(μr−1)H=(500−1)×500Am−1

=499×500Am−1=2.495×105Am−1

≈2.5×105Am−1

Answer 2

Answer:

2.495 × 10 power 5

am-1

Explanation:

(500 -1)×500×1

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