Question

A solenoid has a cross-sectional area of 8 x 10-4 m2, 300 windings, length of 0.4 m, and a current of 1.2 A.

A) 5 x 10-7 Wb

B) 9 x 10-4 Wb

C) 2.7 x 10-4 Wb

Answer 1

Given:

cross-sectional area of solenoid A = 8 x 10⁻⁴ m²

no of windings N = 300

length of solanoid L = 0.4 m

current I =1.2 A

To find:

magnetic flux of the coil B =?

Step-to-step-explanation:

• The magnetic flux flowing through the solenoid is given by

        φ = BA

         = $\displaystyle \frac{\mu_0 N I}{l} \ A$

         where

         φ = magnetic flux flowing through the solenoid

         B=  magnetic field

         μ₀ = the permeability of free space

         N =  no of windings of the solenoid

          I = current

         L = length of solanoid

        A = cross-sectional area of solenoid

• Now we will calculate the magnetic flux flowing through the solenoid by putting the given values in the above equation:

        $\displaystyle \phi = \frac{4 \pi \times 10^{-7} \times\ 300 \ \times\ 1.2\ \times\ 8 \times10^{-4}}{0.4}$

        φ = 90432 × 10⁻¹¹

        φ = 9  × 10⁻⁷ Wb

• Hence required magnetic flux flowing through the solenoid is 9×10⁻⁷Wb.

Answer 2

Answer:

Given:

cross-sectional area of solenoid A = 8 x 10⁻⁴ m²

no of windings N = 300  

length of solanoid L = 0.4 m  

current I =1.2 A  

Explanation:

To find:

magnetic flux of the coil B =?

The magnetic flux flowing through the solenoid is given by

       φ = BA  

where

φ = magnetic flux flowing through the solenoid

 B=  magnetic field

μ₀ = the permeability of free space

N =  no of windings of the solenoid

I = current

L = length of solanoid

A = cross-sectional area of solenoid

Now we will calculate the magnetic flux flowing through the solenoid by putting the given values in the above equation:

 φ = 90432 × 10⁻¹¹

φ = 9  × 10⁻⁷ Wb

Hence required magnetic flux flowing through the solenoid is 9×10⁻⁷Wb.