Question

A solenoid has a diameter of 20cm length of 10cm the current in the solenoid is 15A and the total number of turns is 10.000. what is the magnetic field inside the solenoid.

Answer 1

$\huge\underline\blue{\sf Answer:}$

$\red{\boxed{\sf Magnetic\:field(B)=1.8×10^{-3}T}}$

$\huge\underline\blue{\sf Solution:}$

$\large\underline\pink{\sf Given: }$

• Diameter of solenoid (d) = 20cm

its radius (r) = 10 cm or 0.1 m

• Current (i) = 15A

• Number of turns (N) = 10

$\large\underline\pink{\sf To\:Find: }$

• Magnetic field inside the solenoid (B) = ?

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We know

Magnetic field for solenoid (B) :-

$\large{\boxed{\sf B=\mu_oni }}$

And

$\large{\boxed{\sf n=\frac{N}{l}}}$

$\large\implies{\sf n=\frac{10}{0.1} }$

$\large\implies{\sf n=100}$

On putting value

$\large\implies{\sf B=\mu_oni}$

Here

$\sf{\mu_o=4π×10^{-7}}$

$\implies{\sf B=4×3.14×10^{-7}×100×15 }$

$\large\implies{\sf B=18840×10^{-7}}$

$\large\implies{\sf B=1.8×10^{-3}T }$

$\red{\boxed{\sf Magnetic\:field(B)=1.8×10^{-3}T}}$

Hence ,

Magnetic field of solenoid is $\sf{1.8×10^{-3}T}$

Answer 2

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