A solenoid has a material of relative permeability 400. If solenoid has 1000 turns per meter & carries a current of 2 A. Find H l.
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- due to solenoid mag field in vacuum
» Bo = μo Ni
» μoNi = μoH
» H = Ni
» 1000/m×2A
» 2×10³ Am-¹
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hey mate see ur answer in attachment
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