A solenoid has a material of relative permeability 400. If solenoid has 1000 turns per meter & carries a current of 2 A. Find Magnetic Intensity.
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- due to solenoid Magnetic field in vacuum;
→Bo= μoNi
→μoNi = μoH
→ H= ni
→ 1000/m×2A
→2× 10³ Am-¹
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