Question

A solenoid having a core of 10^-3 Square metres on cross section, half air(relative permeability=1) and half iron (rel. Permeability=5) is 1m long, the number of turns are 2000. What is the coefficient of self induction?
(1)0.5 H
(2)0.75 H
(3)1. 26 H
(4)2.25 H

Answer 1

Answer:

Explanation:

dot know

c is your answer

Answer 2

The coefficient of self induction is 1.26 H.

(3) is correct option.

Explanation:

Given that,

Length = 1 m

Cross section area $A= 10^{-3}\ m^2$

Number of turns N = 2000

Number of turns per meter $n=\dfrac{N}{l}$

$n=\dfrac{1000}{\dfrac{1}{2}}$

$n=2000\ turn/m$

Relative permeability of air =1`

Relative permeability of air =500

We need to calculate the coefficient of self induction

Using formula of self induction

For air,

$L=\mu_{0}\mu_{a}n^2 Al$

Put the value into the formula

$L=4\pi\times10^{-7}\times1\times(2\times10^{3})^2\times10^{-3}\times\dfrac{1}{2}$

$L=8\pi\times10^{-4}\ H$

For iron,

$L=\mu_{0}\mu_{a}n^2 Al$

Put the value into the formula

$L=4\pi\times10^{-7}\times500\times(2\times10^{3})^2\times10^{-3}\times\dfrac{1}{2}$

$L=40\pi\times10^{-2}\ H$

We need to calculate the total coefficient of self induction

$L=L_{a}+L_{I}$

Put the value into the formula

$L=8\pi\times10^{-4}+40\pi\times10^{-2}$

$L=1.26\ H$

Hence, The coefficient of self induction is 1.26 H.

Learn more :

Topic : Coefficient of self induction

https://brainly.in/question/11151203