Question

A solenoid of 200 turns per unit metre have a current of 25 A flowing through it. Calculate the magnitude of the magnetic field created

ANSWER NEEDED URGENTLY

Answer 1

Answer:

first i am sorry for my bad language but i will explain it as far as i can!

second the answer is ($2.5*10^{-4$) i cant type it but the minus 4 above the 10

Explanation:

how i solved this ok!

there is a law says (μ* $\frac{N}{I}*I$)

μ: Modulus of permeability of the medium Since the solenoid is in the air, the air permeability coefficient will be ($4\pi*10^{-7$)

N: number of turns

i: Electric current intensity

write them in their right place in the law then the result will appear after that.

i wish that i could explain what i done

bey.