Question

A solenoid of length 50 cm has four
layers. Each layer has 350 turns. Radius of the innermost layer is 1.4 cm. If current flowing in the solenoid is 6 A, the intensity of the magnetic field at the ends the solenoid is: ​

Answer 1

Explanation:

total no. of turns = no. of layers × no. of turns per layers

n = (350 × 4) for length = 50m

for 100cm

n = ( 2×4×350)

n= 2500

magnetic field intensity of the end of solenoid

B = MoNi / 2

B = 12.57 × 10-⁷× 2500 × 6 / 2

B = 1.05×10-² Joule