Question

a solenoid of length 50 cm with 20 turns per cm and area of cross section 40 cm square completely surrounds another co axial solenoid of the same length , area of cross section25 cm square with 25 turns per cm . calculate the mutual induction of the system​

Answer 1

The mutual inductance will be 7.85×10^(-3) H

Explanation:

Length = l = 50cm=1/2 m

Total no. of turns in one solenoid = N1=20×50 =1000

Area of cross section of outer solenoid = A1=40cm^2=40×10-4m^2

Total no .of turns in inner solenoid =N2=25×50=1250N

Area of cross section of inner solenoid = A2=25cm^2=25×10-4 m^2

Now we know that,

M=μ0N1N2A2M/l    ………. (i)

By putting values in equation in i we get,

M =7.85×10^(-3) H

Answer 2

Answer:

The mutual inductance will be 7.85×10^(-3) H

Explanation:

Length = l = 50cm=1/2 m

Total no. of turns in one solenoid = N1=20×50 =1000

Area of cross section of outer solenoid = A1=40cm^2=40×10-4m^2

Total no .of turns in inner solenoid =N2=25×50=1250N

Area of cross section of inner solenoid = A2=25cm^2=25×10-4 m^2

Now we know that,

M=μ0N1N2A2M/l    ………. (i)

By putting values in equation in i we get,

M =7.85×10^(-3) H