a solenoid ofdiameter 5cm is 25cm long has 250 turns if the current in it is 5A . Find B
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length of the solenoid l =25cm=0.25m
number of turn N=250
but N=N/l= 250/0.25=1000
current I =5A
magnetic field B=mew nI
B=4pi x10^-7x 1000 x5 [ mew=4 pi x10^-7 Tm/A
B=62400x10^-7 T
number of turn N=250
but N=N/l= 250/0.25=1000
current I =5A
magnetic field B=mew nI
B=4pi x10^-7x 1000 x5 [ mew=4 pi x10^-7 Tm/A
B=62400x10^-7 T
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