Question

a solid AB has NaCl structure. If the radius of cation A is 100 pm, what is the radius of the anion B?​

Answer 1

Answer:

-100

Explanation:

becauz the cation is positive and anion is negative then it will be -100

Answer 2

${\huge{\boxed{\red{\tt{\purple{ANSWER}}}}}}$

Expected maximum size of anion is 242 pm

Explanation:

Solid AB has NaCl structure

NaCl has FCC lattice. The coordination number of each ion in this solid is 6 and the limiting radius ratio is in the range 0.414-0.732.

Now, radius ratio = r-/r+

or, r− = radiusratio r+

Thus for maximum radius of the Anion, we have to take the minimum ratio

taking radius ratio as 0.414, we get

r- = 0.414/100 pm

or r- = 241.54 pm ≈ 242 pm

hope it helps...

mark as brainliest