Question

A solid ab has nacl type structure with edge length

Answer 1

Answer:what are you asking for

Explanation:please give proper question

Answer 2

Hii Dear,

◆ Complete question should be -

Q. A solid AB has NaCl type structure with edge length 580 pm. The radius of A+ is 100 pm. Find the radius of B- ?

◆ Answer -

r- = 190 pm

◆ Explanation -

# Given -

a = 580 pm

r+ = 100 pm

# Solution -

NaCl shows face-centered cubic structure.

In FCC,

r+ + r- = a/2

100 + r- = 580/2

100 + r- = 290

r- = 290 - 100

r- = 190 pm

Therefore, radius of B- ion in solid AB is 190 pm.

Hope this helped you.