Physics, asked by zainmd9562, 11 months ago

A solid at temperature T1 is kept in an evacuated chamber at temperature T2 > T1. The rate of increase of temperature of the body is proportional to
(a) T2 − T1
(b) T22 - T21
(c) T32 - T31
(d) T42 - T41

Answers

Answered by shilpa85475
1

A solid at temperature T1 is kept in an evacuated chamber at temperature T2 > T1. The rate of increase of temperature of the body is proportional to  T42 - T41

Explanation:

  • \mathrm{T}_{2}^{4}-\mathrm{T}_{1}^{4} The thermal radiation energy released per unit time by a black body of surface area A is given by Stefan-Boltzmann law.
  • u=\sigma A T^{4}
  • Stefan-Boltzmann is constant here.
  • Because the solid's temperature is lower than the surroundings, the solid's temperature will rise with time until it reaches a balance with the surroundings. The solid emission rate is proportional to T_{1}^{4} and the surrounding emission rate is proportional to T_{2}^{4} .
  • The net temperature rise rate will therefore be proportional to \mathrm{T}_{2}^{4}-\mathrm{T}_{1}^{4}.

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