Question

A solid ball 300cm in diameter is submerged in a lake of such depth that pressure exerted by water is 9.8*10^4 Nm^-2.Find the change in volume of the ball at this depth. Bulk modulus of ball =10^12Nm^-2

Answer 1

Answer:

Explanation:

Radius of ball=150 cm

Volume =4/3 pi r³

=1.4×10^7 cm³

Pressure=1 kg wt.

=9.8*10 ^5 dyne cm^-2

Therefore,del.v=p*v/k =137.2 cm^2.

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