Question

A solid ball of mass 5kg occupies a volume of 240cm^3.how much will it weigh when immersed completely in a fluid of density 2.7*10^3 kgm^-3

Answer 1

Answer: 42.65 N

Explanation:

weight of the ball outside fluid, W=mg = 5 kg × 9.8 m/s² = 49 N

When ball would be immersed in the fluid, buoyant force would act in the upward direction. Because of this the weight would reduce because the net force in the downward direction would be less.

Buoyant force acting on the ball = weight of the volume of fluid displaced by the ball.

B = ρ V g

where ρ is the density of the fluid, V is the volume of the solid ball and g is the acceleration due to gravity.

B=2.7×10³kg/m³×240×10⁻⁶m³ × 9.8 m/s²= 6.35 N

Hence, when the solid ball is completely immersed in the fluid, it would weigh :

W'=W-B

⇒W'=49 N - 6.35 N= 42.65 N

Answer 2

Answer:42.65 N

Explanation: