Question

a solid body of weight 9 newton is suspended by a string inverter tension in the string is 7.5 Newton find a the loss of weight of the solid in water be the by on force as directed by water on the solid see the volume of the body and the tension in the string is only half the volume of the body is immersed in water take density of water as 1000 kg to cubic metre

Answer 1

Answer:

Since, Weight of the body in water = Tension in the string by which the body is suspended. ∴ Weight of the body in water = 7.5 N. Loss in weight = Weight of the body in air - Weight of the body in Water. ∴ Loss in Weight = 1.5 N.