Question

A solid body weighs 2.10 N inair. its relative density is 8.4. How much will the body weigh if placed in
(i) in water,
(ii) in a liquid of relative density 1.2 ?

Answer 1

Answer:

Now, Relative density = weight of solid in air/ loss of weight of solid in water. Loss of weight of solid in water = weight of solid in air/ Relative density. Loss of weight of solid in water = 2.10/8.4 = 0.25 N. Weight of solid in water = 2.10 - 0.25 =1.85 N.

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