Question

A solid body weighs 234N. When placed on a wooden plank, the area of contact is found to be 10 squre meter. Find the pressure exerted by the brick on the ground?



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Answer 1

Answer:

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Correct Question =

A solid object weighs 250N. When placed on a wooden plank, the area of contact is found to be 10 meter square. Find the pressure exerted by the solid object on the wooden plank.

Solution =

• Weight of the body = 250N

• Area of contact = 10m^2

Since the units are all in SI , there is no need to convert them.

• Pressure = force × area

• Here the force = Weight

• Pressure = 250 × 10

$= \: {2500m}^{2}$

Hence the pressure exerted by the Object on the plank = 2500N/m^2

#Be Brainly :)

Answer 2

Required Answer:-

Given:

• Weight of solid body - 234N.
• Area of contact - 10m².

To Find:

• The pressure exerted.

Solution:

Here,

→ Force (F) = 234N

→ Area of Contact (A) = 10m²

We know that,

→ Pressure = Force / Area

i.e., pressure is the force exerted on a unit area.

Putting the values, we get,

→ P = 234/10 N/m²

→ P = 23.4 N/m²

→ P = 23.4Pa (∵ 1N/m² = 1Pa)

→ Therefore, the pressure exerted on the ground is 23.4Pa

Answer:

• The pressure exerted on the ground will be - 23.4 Pa.