Question

a solid body weighs 300N.when placed on a wooden plank, the area of contact is found to be 6m². find the pressure exerted by the solid body on the wooden plank. pls answer correctly ​

Answer 1

Answer:

Pressure = $\frac{force}{Area}$

Pressure = $\frac{300}{6}$

Pressure = $\frac{50}{1}$

Pressure = $50$

Hence the pressure on the wooden plank exerted by the solid body was 50 N/m²

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Answer 2

Given:

A solid body weighs 300N. The area of contact is found to be 6m².

To find:

Pressure exerted by body?

Calculation:

• Pressure is a scalar quantity factorise by the ratio of perpendicular force vector (i.e. thrust) and area. In other words, it refers to the force per unit area.

$\therefore \: P = \dfrac{F}{area}$

$\implies \: P = \dfrac{300}{6}$

$\implies \: P = 50 \: Pascal$

So, pressure exerted by object is 50 Pascal.