Question

a solid body weights 2n in air .its relative density is 8.how much will the body weight if places in water?
please give the correct ans with explanation ​

Answer 1

Answer:

96N

Explanation:

Given that,

Weight of body in air = 100 N

Buoyant force = Weight of liquid displaced

Volume of water displaced = 400 cc²

Density of water = 1g/cm³

In this case,

ρ= m/V

m=ρ×V

m=1×400

m=400g.

We know that,

The weight of water displaced is

W=m×g

W= 2/5 × 9.8

W=3.92N

Now, weight of the object in water

W=100−3.92

W=96.08

W=96N.

Hence, the weight of object in water is 96 N.

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