Question

A solid brass sphere of volume 0.305 m3 is dropped in ocean, where water pressure is 2 x 10' N/m². The bulkbmodulus of water is 6.1 x 1010 N/m2.What is the change in volume of sphere?​

Answer 1

Answer:

Given, water pressure , P = 2 × 10^7 N/m²

Bulk modulus of water , = 6.1 × 10^10 N/m² .

Volume of solid brass sphere , V = 0.305 m³

Now use formula,

[ didn't include sign ]

6.1 × 10^10 = 2 × 10^7/(∆V/0.305)

∆V = 2 × 10^7 × 0.305/6.1 × 10^10

= 0.610 × 10^7/6.1 × 10^10

= 10^-4 m³