A solid circular cone of radius R is joined to a uniform solid hemisphere of radius R. Both are made of same material. The center of mass of composite solid lies at the common base. Find the height
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ANSWER
REF.Image.
Volume of cone =
3
1
πr
3
h
Mass of cone, m
1
=p×
3
1
πr
2
h
Mass of hemisphere, m
2
=p×
2
1
×
3
4
πr
3
=p×
3
2
πr
3
Now, Y=
m
1
+m
2
m
1
y
1
+m
2
y
2
0=
p×
3
1
πr
2
h+p×
3
2
πr
3
p×
3
1
πr
2
h×
4
h
+p×
3
2
πr
3
(−
8
3r
)
or p×
3
1
πr
2
[
4
h
2
−2r×
8
3r
]=0
or
4
h
2
−
4
3r
2
=0 or h=
3
r
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