Question

A solid circular shaft is rotating at 180 r.p.m. Calculate
the power developed if the torque is a 40000N-mm.​

Answer 1

Given info : A solid shaft is rotating at 180 rpm.

To find : the power developed if the torque is 40000 N-mm.

solution : angular frequency of circular shaft, ω = 180 rpm = 180 × 2π/60 rad/s

= 6π rad/s

torque , τ = 40000 N-mm = 40000 × 10¯³ Nm

= 40 Nm

now power developed, W = τ × ω

= 40 × 6π Watt

= 240 × 3.14 watt

= 753.6 watt

Therefore the power developed by circular shaft is 753.6 watt

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Answer 2

Step-by-step explanation:

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