Question

A solid circular shaft transmit 20 kN-m torque if maximum shear stress is 45 MPa then dia of the shaft will be

Option 1: 13.13 cm

Option 2: 7.25 cm

Option 3: 16.15 cm​

Answer 1

Answer:

Option 1

Explanation:

Concept:

Strength of the Solid Shaft of Circular Cross-Section

where T = Turning force or torque, τ = Maximum shear stress and D = Diameter of the cross-section.

Calculation:

Given:

T = 1570 N-m = 1570 × 103 N-mm, D = 20 mm, and τ = ?

τ = 999.41 ≈ 1000 N/mm2 = 1000 MPa