A solid compound XY has NaCl structure. If the radius of
the cation is 100 pm, the radius of the anion (Y⁻) will be :
(a) 275.1 pm (b) 322.5 pm
(c) 241.5 pm (d) 165.7 pm
Answers
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The radius of the anion (Y⁻) will be 241.5 pm. Thar's why option c is correct.
Explanation:
A solid compound XY has NaCl structure. If the radius of the cation is 100 pm, the radius of the anion (Y⁻) will be 241.5 pm.
The radius ration = 0.414
Radius of Cl⁻ = ?
Radius of Na⁺ = ?
Solution:
Radius ratio = radius of cation / radius of anion
Radius ratio = 100 pm / radius of anion
radius of anion = 100 pm / 0.414
radius of anion = 241.5 pm
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