Question

A solid compound (XY) has NaCl type structure. If the radius of cation is 120 pm, the edge length of unit cell of XY will be 819.71 pm 772.25 pm 901.55 pm 715.68 pm

Answer 1

A solid compound (XY) has NaCl type structure. radius of the cation is 120 pm.

To find : The edge length of unit cell of XY.

solution : ratio of the radii of cation to anion for NaCl structure is given by,

$\quad\frac{r^+}{r^-}=0.414$

so, radius of anion, r¯ = r⁺/0.414

= 120/0.414 = 289.855 pm

now edge length of XY ( NaCl structure) = 2(r⁺ + r¯)

= 2(120 + 289.855)

= 2 × 409.855

= 819.71 pm

Therefore the edge length of unit cell of XY is 819.71 pm.

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