A solid conductor has a cross-section area 1 cm2 and 2cm2 as shown in the figure. A current of 20A entering at A. Then
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Answer:
The relation between current and drift velocity
I.e1=V
d
.e.n.a
where I= current
V
d
= current velocity
e= electron
n= no. of electrons per unit volume
a= area of cross section
Now, V
d
=
nea
I
=
1×10
−4
×9×10
7
×28
10
=1.94×10
−3
m/s
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