A solid cone of height 25 cm and base diameter 25 cm floats in water with its vertex
downwards such that 20 cm of its axis is immersed. The additional weight that must
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Answer: 2 kg
Explanation:
buoyancy force at present( immersed height = 20cm)(b1) = mass of the cone.
buoyancy after adding weight(let m) (b2) = mass of cone + m
m = b2 - b1
=1/3*3.14( (25^3)/4 - 2000 )*1/1000
= additional weight required in kg
Answered by
0
Answer:
Explanation:
buoyancy force at present( immersed height = 20cm)(b1) = mass of the cone.
buoyancy after adding weight(let m) (b2) = mass of cone + m
m = b2 - b1
=1/3*3.14( (25^3)/4 - 2000 )*1/1000
= additional weight required in kg
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