a solid cone of radius r and height h is placed over a cylinder having same base radius and height as that of a cone. what is the total surface area of the combined solid?
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Step-by-step explanation:
False
We know that , total surface area of cone of radius, r
and " "height, h = Curved surface Area + area of base =πrl+πr2
where, " "l=h2+r2−−−−−−√
and total surface area of a cylinder of bases radiur, r and height , h = Curved surface area + Area of both bases =2πrh+πl2
Hence, when we placed a cone over a cylinder, then one base in common for both .
So, total surface area of the combined solid
=[πrl+2πrh+π2=πr[l+2h+r]
=π[r2+h2−−−−−−√+2h+r]
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