A solid consisting of a right circular con of height 120 cm and base diameter 24 cm , which is surmounted by another cylinder of height 60 cm and radius 8 cm. Find the mass of the pole , given that 1 cm³ of iron has approximately 8g mass . (use π = 3. 14 )
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Step-by-step explanation:
Given:
Radius (r) of hemispherical part = Radius (r) of conical part =60cm
Height (h
1
) of conical part of solid =120 cm
Height (h
1
) of cylinder =180 cm
Radius (r) of cylinder =60 cm
Volume of water left = Volume of cylinder - Volume of solid
= Volume of cylinder - (Volume of cone + Volume of hemisphere)
=πr
2
h
1
−[
3
1
πr
2
h
2
+
3
2
πr
3
]
=π×60
2
×(180)−[
3
1
π×60
2
×120+
3
2
π×60
3
]
=π(60)
2
[180−(40+40)]
=π(3600)[100]
=3,60,000×
7
22
=1131428.57 cm
3
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