a solid consisting of a right circular cone of height 120cm and radius 60cm standing on a hemisphere of radius 60cm is placed upright in a right circular cylinder full of water such that it touches the bottom. find the volume of water keft in the cylinder if the radius and height are 60 and 180cm
Answers
Step-by-step explanation:
volume of cylinder = π r ²h
22/7 (60)² ×180 = 2036571.429 cm ³
h of cone = 180-60 = ,120cm
volume of cone = 452571.4286 cm³
r = 60 cm
volume of hemisphere = 42571.4286 cm³
volume of water left in cylinder = volume of cylinder - volume of cone + hemisphere
= 1.131 m³ approx
hence volume of water left in the cylinder is 1.131 m³.
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Step-by-step explanation:
Volume of Water left in Cylinder = 1131428.57 cm³
Step-by-step explanation:
Given: Height of Cone, h = 120 cm and Radius of Cone, r = 60 cm
Radius of Hemisphere, r = 60 cm
Height of Cylinder, H = 180 cm and Radius of Cylinder, r = 60 cm
To find: Volume of water left in cylinder
Volume of water left in cylinder = volume of cylinder - ( volume
of cone + volume of hemisphere )
= \pi r^2H-(\frac{1}{3}\pi r^2h+\frac{2}{3}\pi r^3)
= \pi r^2(H-(\frac{1}{3}h+\frac{2}{3}r))
= \frac{22}{7}\times60^2(180-(\frac{1}{3}\times120+\frac{2}{3}\times60))
= \frac{22}{7}\times3600(180-(40+40))
= \frac{22}{7}\times3600\times100
= 1131428.57 cm³
Therefore, Volume of Water left in Cylinder = 1131428.57 cm³