a solid consists of cylinder of base base radius of
2.5 cm and height of 8 cm and a
cuboid with dimensions 11cm by 7 cm by 3 cm
Answers
Given :- a solid consists of cylinder of base base radius of 2.5 cm and height of 8 cm and a cuboid with dimensions 11cm by 7 cm by 3 cm .
To Find :-
- Volume of solid ?
- Total Surface area of solid ?
Solution :-
we know that,
- Volume of cylinder = π * (radius)² * height .
- Volume of cuboid = length * breadth * height .
So,
→ Volume of solid = volume of cylinder + volume of cuboid
→ Volume of solid = π * (2.5)² * 8 + 11 * 7 * 3
→ Volume of solid = 3.14 * 6.25 * 8 + 77 * 3
→ Volume of solid = 157 + 231
→ Volume of solid = 388 cm³ (Ans.)
Now,
→ Total Surface area of solid = CSA of cylinder + Top Base area of cylinder + TSA of cuboid
→ Total Surface area of solid = 2πrh + πr² + 2(lb + bh + hl).
→ Total Surface area of solid = (2 * 3.14 * 2.5 * 8) + {3.14 * (2.5)²} + {2(11*7 + 7*3 + 3*11)}
→ Total Surface area of solid = 125.6 + 19.625 + 262
→ Total Surface area of solid = 407.225 cm². (Ans.)
Hence, Volume of solid is 388 cm³ and Total Surface area of solid is 407.225 cm².
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