Question

A solid crystalline oxide with formula A3 BO3 has oxide ions arranged in ccp while ions of metal A and metal B are occupying tetrahedral void and octahedral void respectively. Calculate percentage space occupied by ions of metal A and B in tetrahedral and Octahedral voids respectively ? (A) 50 %, 33.33 % (B) 33.33 %, 12.5 % (C) 25 %, 12.5 % (D) 50 %, 25 %

Answer 1

Answer:

The answer is option (A)

Explanation:

Explanation is given in the attached photo.

Answer 2

A.50%,33.33%

Explanation:

The given formula of the compound is $A_3BO_3$

By multiplying by 4/3

Then we get

The formula compound

$A_4B_{\frac{4}{3}}O_4$

Metal A occupies tertrahedral void and metal B occupies octahedral void

We are given that oxide ions are arranged  in CCP lattice

Number of atom of metal A=4

Number of atom of metal B=$\frac{4}{3}$

Total number of tetarhedral void=8

Total number of octahedral void=4

Space filled by tetrahedral void=$\frac{4}{8}\times 100=50$%

Space filled by Octahedral void=$\frac{4}{3\times 4}\times 100=33.33$%

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