A solid cube of iron 53cm×40cm×15cm is melted and recast in cylindrical pipe and outter and inner radius of pipe is 8and 7 cm respectively find lenght of pipe
Answers
Volume of the Cuboid= l×b×h,
= 53×40×15,
=31800 cm³.
So, volume of the iron which makes the rod= 31800 cm³,
Inner radius, r = 7 cm,
Outer Radius, R= 8 cm.
Then, volume of the pipe= Area of the ring × height.
= (π R²-π r²)× h,
= π (R²-r²)× h = 53× 40× 15,
(8²-7²)× h= 53× 40× 15 × 7/22,
(64-49)× h= 53× 40× 15× 7/22,
h = 53× 40× 15× 7/22× 15,
So, Height= 53× 40× 7/22,
= 674.54 cm (approximately).
Answer:
Volume of cuboid = 53 × 40 × 15
= 31800 cm³
Volume of hollow-cylinder = πh (R² - r²)
= 22/7 × h (4² - 3.5²)
= 22/7 × h (16 - 12.25)
= 22/7 × h * 3.75
31800 = 22/7 × h × 3.75
222600 = 22 × h × 3.75
222600 = 82.5 × h
h = 222600/82.5
= 2698.18 cm